Solve Civ 7’s Papyrus Problem: Get Science Boost!

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In the game known as “Civilization 7“, individuals treading along the Science Legacy Path may stumble upon a narrative event called “The Papyrus Problem“. This narrative event challenges players to unravel a mathematical conundrum, a puzzle whose roots extend further back than you’d imagine, and whose solution is more complex than it initially appears.

As a dedicated gamer immersed in the world of Civilization 7, I’ve found myself grappling with an intriguing conundrum known as the Papyrus Problem. When faced with a Narrative Event that presents me with two options, my decision-making skills are put to the test. This guide aims to shed light on why choosing option A over B is the wiser move, offering a glimpse into the fascinating real-life history that inspired this unique riddle.

Origins Of The Civ 7 Papyrus Problem

In Civilization VII, the Papyrus Problem event is a nod to a genuine mathematical puzzle often called the “Seven Houses Enigma.” It shares some resemblance with the well-known nursery rhyme about a trip to St. Ives, known as “As I Went To St. Ives.

The Papyrus Problem, which can be traced back to the realm of ancient Egyptian mathematics, might be why it’s featured in Civ 7. This mathematical puzzle, known as the Rhind Mathematical Papyrus, is housed in the British Museum and shares similarities with the Seven Houses Riddle, a problem more familiar today.

Civ 7 Papyrus Problem Answer

In total, there are 7 houses, and each house is home to 7 felines. Every one of these cats manages to hunt down 7 mice daily. In turn, each mouse consumes 7 grains of barley per day. If every grain had been able to grow into a full crop, it would have yielded 7 gallons of cereal.

What is the sum of the enumerated things?

In the Papyrus Problem of Civilization VII, there are two possible solutions: either 16807 or 19607. The solution you obtain relies on how you approach and solve this particular problem.

In Civilization VII, solving the Papyrus Problem isn’t as straightforward as one might initially think. While your first thought may be to calculate 7 multiplied by itself four times, it’s crucial to note that the riddle asks for the “sum” of the “individually listed” items.

Rather than computing 7 multiplied by itself five times (7^5), you should instead add up the results from separately multiplying 7 by itself for each number between 1 and 5.

To solve the Papyrus Problem independently, follow these steps:

1. Multiply 7 by itself four times (7^4).
2. Then, multiply 7 by itself three times (7^3).
3. Next, multiply 7 by itself twice (7^2).
4. After that, just multiply 7 by 1 (7).
5. Add all these values together: 7^4 + 7^3 + 7^2 + 7.
6. Your total should be equivalent to the sum of 16,807, 2,401, 343, 49, and 7.

Because it is included in this calculation, we can immediately ignore the first choice.

By summing up every single quantity listed, you will arrive at the total of 19607. This achievement marks the completion of one of mathematics’ oldest problems, dating back to ancient Egypt. And if you manage to crack the Papyrus Problem in Civ 7, you’ll be given a cool +100 enhancement to your Science score.

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2025-02-13 07:56